問題描述

大神們：

我想把htm文件中的第一個(gè)<link到第二個(gè)<link之間的所有內(nèi)容另存為一個(gè)htm該怎么寫比較簡(jiǎn)潔。

<meta http-equiv='X-UA-Compatible' content='IE=edge'><link rel='prefetch' ><meta name='application-name' content='Python.org'><meta name='msapplication-tooltip' content='The official home of the Python Programming Language'><meta name='apple-mobile-web-app-title' content='Python.org'><meta name='apple-mobile-web-app-capable' content='yes'><meta name='apple-mobile-web-app-status-bar-style' content='black'><meta name='viewport' content='width=device-width, initial-scale=1.0'><meta name='HandheldFriendly' content='True'><meta name='format-detection' content='telephone=no'><meta http-equiv='cleartype' content='on'><meta http-equiv='imagetoolbar' content='false'><script type='text/javascript' async='' src='https://ssl.google-analytics.com/ga.js'></script><script src='http://www.intensediesel.com/wenda/Welcome to Python.org_files/modernizr.js.下載'></script><style type='text/css' adt='123'></style><link href='http://www.intensediesel.com/wenda/Welcome to Python.org_files/style.css' rel='stylesheet' type='text/css'><link href='http://www.intensediesel.com/wenda/Welcome to Python.org_files/mq.css' rel='stylesheet' type='text/css' media='not print, braille, embossed, speech, tty'>

提取的內(nèi)容應(yīng)該是：

<link rel='prefetch' ><meta name='application-name' content='Python.org'><meta name='msapplication-tooltip' content='The official home of the Python Programming Language'><meta name='apple-mobile-web-app-title' content='Python.org'><meta name='apple-mobile-web-app-capable' content='yes'><meta name='apple-mobile-web-app-status-bar-style' content='black'><meta name='viewport' content='width=device-width, initial-scale=1.0'><meta name='HandheldFriendly' content='True'><meta name='format-detection' content='telephone=no'><meta http-equiv='cleartype' content='on'><meta http-equiv='imagetoolbar' content='false'><script type='text/javascript' async='' src='https://ssl.google-analytics.com/ga.js'></script><script src='http://www.intensediesel.com/wenda/Welcome to Python.org_files/modernizr.js.下載'></script><style type='text/css' adt='123'></style><link

問題解答

import retext = ''with open('read.html', 'r') as rf: text = rf.read() pattern = r'<link[sS]*?<link'results = re.findall(pattern, text)if results: r = results[0] with open('write.html', 'w') as wf:wf.write(r) ================================================with open('read.html', 'r') as rf: with open('write.html', 'w') as wf:num = 0for line in rf.readlines(): if line.startswith('<link'):num += 1continue if num == 2:break wf.writelines(line)